What is the tangent of f(x)=3x^2,\at x=(6) ?

The tangent of f(x)=3x^2,\at x=(6) is y=36x-108

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=3x^2,\at x=(6)

tangent of

f (x) = 3 x^{2}, at x = (6)

y = 36 x - 108

Solution steps

Find the tangent point:

(6, 108)

Find the slope of

f (x) = 3 x^{2} : \frac{df ( x )}{d x} = 6 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 36

Find the line with slope m=

36

and passing through

(6, 108) : y = 36 x - 108

y = 36 x - 108

x \to 1 + lim (\frac{1}{x ^{3} - 1})

f (x) = tan^{3} (x)

\int_{1}^{e^{4}} x^{3} ln (x) d x

\int sin^{0} (x) d x

\int_{0}^{8} (8 y - y^{2}) d y

What is the tangent of f(x)=3x^2,\at x=(6) ?
The tangent of f(x)=3x^2,\at x=(6) is y=36x-108