What is (\partial)/(\partial t)(e^{-2t}cos(x)) ?

The answer to (\partial)/(\partial t)(e^{-2t}cos(x)) is -2e^{-2t}cos(x)

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(\partial)/(\partial t)(e^{-2t}cos(x))

\frac{\partial}{\partial t} (e^{- 2 t} cos (x))

- 2 e^{- 2 t} cos (x)

Solution steps

\frac{\partial}{\partial t} (e^{- 2 t} cos (x))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (x) \frac{\partial}{\partial t} (e^{- 2 t})

Apply the chain rule:

e^{- 2 t} \frac{\partial}{\partial t} (- 2 t)

= e^{- 2 t} \frac{\partial}{\partial t} (- 2 t)

\frac{\partial}{\partial t} (- 2 t) = - 2

= cos (x) e^{- 2 t} (- 2)

Simplify

= - 2 e^{- 2 t} cos (x)

x \to 0 lim (sin (\frac{7}{x}))

f (x) = \frac{9}{x}, at x = 1

\frac{d}{d t} (f (t) (t)^{- 1})

\int 18 cos (2 t) d t

\frac{d}{d t} (3 t - 1)

What is (\partial)/(\partial t)(e^{-2t}cos(x)) ?
The answer to (\partial)/(\partial t)(e^{-2t}cos(x)) is -2e^{-2t}cos(x)