What is the integral of 1 (e^x) ?

The integral of 1 (e^x) is de^x+C

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integral of 1 (e^x)

\int \frac{d}{1} (e^{x}) d x

d e^{x} + C

Solution steps

\int \frac{d}{1} e^{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= d \cdot \int e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= d e^{x}

Add a constant to the solution

= d e^{x} + C

\frac{d}{d x} (\frac{6}{x + 4})

(15, 250), (20, 111)

\frac{8 - x}{5} + \frac{16 + x ^{2}}{3}

\frac{d}{d x} (\frac{x ^{2}}{2 ^{x} - 1})

\int \frac{1}{x 16 x ^{2} - 1} d x