What is the derivative of sin^2(3+x) ?

The derivative of sin^2(3+x) is sin(2(3+x))

What is the first derivative of sin^2(3+x) ?

The first derivative of sin^2(3+x) is sin(2(3+x))

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\frac{d}{d x} (sin^{2} (3 + x))

sin (2 (3 + x))

Solution steps

\frac{d}{d x} (sin^{2} (3 + x))

Apply the chain rule:

2 sin (3 + x) \frac{d}{d x} (sin (3 + x))

= 2 sin (3 + x) \frac{d}{d x} (sin (3 + x))

\frac{d}{d x} (sin (3 + x)) = cos (3 + x)

= 2 sin (3 + x) cos (3 + x)

Use the Double Angle identity:

2 sin (x) cos (x) = sin (2 x)

= sin (2 (3 + x))

\frac{d y}{d x} = (\frac{( 4 y + 3 )}{8 x + 5})^{2}

x \to 6 lim (4 x + ∣ x - 6 ∣)

f (x) = x^{3} + x^{2} - 2 x

x \to 2 lim (\frac{2 x + 1}{x + 2})

\frac{d}{d x} (16 e^{2 x} x + 32 e^{2 x})

What is the derivative of sin^2(3+x) ?
The derivative of sin^2(3+x) is sin(2(3+x))
What is the first derivative of sin^2(3+x) ?
The first derivative of sin^2(3+x) is sin(2(3+x))