What is the solution for y^{''}-(2/t)y^'+(2/(t^2))y=0 ?

The solution for y^{''}-(2/t)y^'+(2/(t^2))y=0 is y=c_{1}t^2+c_{2}t

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y^{''}-(2/t)y^'+(2/(t^2))y=0

y^{^{''}} - (\frac{2}{t}) y^{^{'}} + (\frac{2}{t ^{2}}) y = 0

y = c_{1} t^{2} + c_{2} t

Solution steps

y^{''} (t) - (\frac{2}{t}) y^{'} (t) + (\frac{2}{t ^{2}}) y = 0

Solve linear ODE:

y = c_{1} t^{2} + c_{2} t

y = c_{1} t^{2} + c_{2} t

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What is the solution for y^{''}-(2/t)y^'+(2/(t^2))y=0 ?
The solution for y^{''}-(2/t)y^'+(2/(t^2))y=0 is y=c_{1}t^2+c_{2}t