What is the derivative of (3x-1^4(2x+1)^{-3}) ?

The derivative of (3x-1^4(2x+1)^{-3}) is (12(3x-1)^3)/((2x+1)^3)-(6(3x-1)^4)/((2x+1)^4)

What is the first derivative of (3x-1^4(2x+1)^{-3}) ?

The first derivative of (3x-1^4(2x+1)^{-3}) is (12(3x-1)^3)/((2x+1)^3)-(6(3x-1)^4)/((2x+1)^4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} ((3 x - 1)^{4} (2 x + 1)^{- 3})

\frac{12 ( 3 x - 1 ) ^{3}}{( 2 x + 1 ) ^{3}} - \frac{6 ( 3 x - 1 ) ^{4}}{( 2 x + 1 ) ^{4}}

Solution steps

\frac{d}{d x} ((3 x - 1)^{4} (2 x + 1)^{- 3})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = (3 x - 1)^{4}, g = (2 x + 1)^{- 3}

= \frac{d}{d x} ((3 x - 1)^{4}) (2 x + 1)^{- 3} + \frac{d}{d x} ((2 x + 1)^{- 3}) (3 x - 1)^{4}

\frac{d}{d x} ((3 x - 1)^{4}) = 12 (3 x - 1)^{3}

\frac{d}{d x} ((2 x + 1)^{- 3}) = - \frac{6}{( 2 x + 1 ) ^{4}}

= 12 (3 x - 1)^{3} (2 x + 1)^{- 3} + (- \frac{6}{( 2 x + 1 ) ^{4}}) (3 x - 1)^{4}

Simplify

12 (3 x - 1)^{3} (2 x + 1)^{- 3} + (- \frac{6}{( 2 x + 1 ) ^{4}}) (3 x - 1)^{4} : \frac{12 ( 3 x - 1 ) ^{3}}{( 2 x + 1 ) ^{3}} - \frac{6 ( 3 x - 1 ) ^{4}}{( 2 x + 1 ) ^{4}}

= \frac{12 ( 3 x - 1 ) ^{3}}{( 2 x + 1 ) ^{3}} - \frac{6 ( 3 x - 1 ) ^{4}}{( 2 x + 1 ) ^{4}}

x y^{^{'}} - y = x^{2} + 5 x - 1

f (x) = 3 x^{5} - 2 x^{4}, at x = 4

\int \frac{8 sin ^{3} ( x )}{x} d x

\int_{0}^{2 π} x e^{- x^{2}} d x

\int 16 sin^{2} (x) cos^{3} (x) d x

What is the derivative of (3x-1^4(2x+1)^{-3}) ?
The derivative of (3x-1^4(2x+1)^{-3}) is (12(3x-1)^3)/((2x+1)^3)-(6(3x-1)^4)/((2x+1)^4)
What is the first derivative of (3x-1^4(2x+1)^{-3}) ?
The first derivative of (3x-1^4(2x+1)^{-3}) is (12(3x-1)^3)/((2x+1)^3)-(6(3x-1)^4)/((2x+1)^4)