What is (\partial)/(\partial x)(7x-3y+4) ?

The answer to (\partial)/(\partial x)(7x-3y+4) is 7

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(\partial)/(\partial x)(7x-3y+4)

\frac{\partial}{\partial x} (7 x - 3 y + 4)

7

Solution steps

\frac{\partial}{\partial x} (7 x - 3 y + 4)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (7 x) - \frac{\partial}{\partial x} (3 y) + \frac{\partial}{\partial x} (4)

\frac{\partial}{\partial x} (7 x) = 7

\frac{\partial}{\partial x} (3 y) = 0

\frac{\partial}{\partial x} (4) = 0

= 7 - 0 + 0

Simplify

= 7

\int_{0}^{1} x^{6} - x d x

y^{^{'}} + y \cdot cos (x) = sin (x) \cdot cos (x)

\int \frac{e ^{x} + sec ^{2} ( x )}{e ^{x} + tan ( x )} d x

\frac{s - 4}{( s ^{2} + 5 ) ^{2}}

What is (\partial)/(\partial x)(7x-3y+4) ?
The answer to (\partial)/(\partial x)(7x-3y+4) is 7