What is the integral from 0 to 1 of (1/(1+x^2)) ?

The integral from 0 to 1 of (1/(1+x^2)) is pi/4

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integral from 0 to 1 of (1/(1+x^2))

\int_{0}^{1} (\frac{1}{1 + x ^{2}}) d x

\frac{π}{4}

Decimal Notation

0.78539 \dots

Solution steps

\int_{0}^{1} \frac{1}{1 + x ^{2}} d x

Use the common integral:

\int \frac{1}{1 + x ^{2}} d x = arctan (x)

= [arctan (x)]_{0}^{1}

Compute the boundaries:

\frac{π}{4}

= \frac{π}{4}

x \to 6 lim (4)

\int 3 x^{2} x^{3} + 1 d x

\int \frac{9 x ^{3}}{1 + x ^{2}} d x

\frac{d}{d x} (e^{- 2 x} \cdot cos (x))

x \to 0 + lim (3 x^{(\frac{x}{2})})

What is the integral from 0 to 1 of (1/(1+x^2)) ?
The integral from 0 to 1 of (1/(1+x^2)) is pi/4