What is the solution for (dQ)/(dt)=14.5-(7Q)/(800-2t) ?

The solution for (dQ)/(dt)=14.5-(7Q)/(800-2t) is Q=2.9(-2t+800)+c_{1}(800-2t)^{7/2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dQ)/(dt)=14.5-(7Q)/(800-2t)

\frac{d Q}{d t} = 14.5 - \frac{7 Q}{800 - 2 t}

Q = 2.9 (- 2 t + 800) + c_{1} (800 - 2 t)^{\frac{7}{2}}

Solution steps

\frac{d Q}{d t} = 14.5 - \frac{7 Q}{800 - 2 t}

Solve linear ODE:

Q = 2.9 (- 2 t + 800) + c_{1} (800 - 2 t)^{\frac{7}{2}}

Q = 2.9 (- 2 t + 800) + c_{1} (800 - 2 t)^{\frac{7}{2}}

\int_{0}^{b} \frac{1}{25 - x ^{2}} d x

x \to - 4 lim (\frac{x ^{2} - 3}{4 - x})

2 x^{3} - x^{2} + 1

y^{^{''}} - 16 y^{^{'}} + 289 y = 4 t - 21 cos (17 t)

n = 1 \sum \infty n 2^{n}

What is the solution for (dQ)/(dt)=14.5-(7Q)/(800-2t) ?
The solution for (dQ)/(dt)=14.5-(7Q)/(800-2t) is Q=2.9(-2t+800)+c_{1}(800-2t)^{7/2}