What is the integral of 1/(e^{-x)} ?

The integral of 1/(e^{-x)} is e^x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(e^{-x)}

\int \frac{1}{e ^{- x}} d x

e^{x} + C

Solution steps

\int \frac{1}{e ^{- x}} d x

Simplify

\frac{1}{e ^{- x}} : e^{x}

= \int e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= e^{x}

Add a constant to the solution

= e^{x} + C

\int \frac{2}{5} - \frac{5}{x} d x

\int \frac{1}{( 11 - 10 x - x ^{2} ) ^{2}} d x

\frac{d}{d x} (\frac{5}{x + 3})

x \to + 0 lim ((1 - 2 x)^{\frac{1}{2}})

(sin (x))^{2 x}