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Popular >

derivative of ln(x^2-3x+1)

Solution

\frac{d}{d x} (ln (x^{2} - 3 x + 1))

Solution

\frac{2 x - 3}{x ^{2} - 3 x + 1}

Solution steps

\frac{d}{d x} (ln (x^{2} - 3 x + 1))

Apply the chain rule:

\frac{1}{x ^{2} - 3 x + 1} \frac{d}{d x} (x^{2} - 3 x + 1)

= \frac{1}{x ^{2} - 3 x + 1} \frac{d}{d x} (x^{2} - 3 x + 1)

\frac{d}{d x} (x^{2} - 3 x + 1) = 2 x - 3

= \frac{1}{x ^{2} - 3 x + 1} (2 x - 3)

Simplify

\frac{1}{x ^{2} - 3 x + 1} (2 x - 3) : \frac{2 x - 3}{x ^{2} - 3 x + 1}

= \frac{2 x - 3}{x ^{2} - 3 x + 1}

Popular Examples

tangent of y=x^2-1,(-3,8)tangent of

y = x^{2} - 1, (- 3, 8)

(\partial)/(\partial x)(6x-5y)

\frac{\partial}{\partial x} (6 x - 5 y)

sum from n=1 to infinity}(-1)^n(\sqrt{n of)/(n+2)

n = 1 \sum \infty (- 1)^{n} \frac{n}{n + 2}

integral of (sqrt(289-x^2))/x

\int \frac{289 - x ^{2}}{x} d x

limit as x approaches 0 of (1+x)^{5/x}

x \to 0 lim ((1 + x)^{\frac{5}{x}})

Frequently Asked Questions (FAQ)

What is the derivative of ln(x^2-3x+1) ?
The derivative of ln(x^2-3x+1) is (2x-3)/(x^2-3x+1)
What is the first derivative of ln(x^2-3x+1) ?
The first derivative of ln(x^2-3x+1) is (2x-3)/(x^2-3x+1)