What is the solution for x^2(dy)/(dx)-2xy=6y^4,y(1)= 1/2 ?

The solution for x^2(dy)/(dx)-2xy=6y^4,y(1)= 1/2 is y=(\sqrt[3]{5}x^2)/(\sqrt[3]{2(-9x^5+29))}

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x^2(dy)/(dx)-2xy=6y^4,y(1)= 1/2

x^{2} \frac{d y}{d x} - 2 x y = 6 y^{4}, y (1) = \frac{1}{2}

Solution steps

x^{2} \frac{d y}{d x} - 2 x y = 6 y^{4}

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What is the solution for x^2(dy)/(dx)-2xy=6y^4,y(1)= 1/2 ?
The solution for x^2(dy)/(dx)-2xy=6y^4,y(1)= 1/2 is y=(\sqrt[3]{5}x^2)/(\sqrt[3]{2(-9x^5+29))}