What is the integral from 0 to 1 of (65)/(x^5) ?

The integral from 0 to 1 of (65)/(x^5) is diverges

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integral from 0 to 1 of (65)/(x^5)

\int_{0}^{1} \frac{65}{x ^{5}} d x

diverges

Solution steps

\int_{0}^{1} \frac{65}{x ^{5}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 65 \cdot \int_{0}^{1} \frac{1}{x ^{5}} d x

Apply the Power Rule

: [- \frac{1}{4 x ^{4}}]_{0}^{1}

= 65 [- \frac{1}{4 x ^{4}}]_{0}^{1}

Compute the boundaries:

diverges

= diverges

y^{^{'}} + 4 x y = 0

\int 4 (2 x + 5)^{3} d x

1 - x^{2}, x = 0

\frac{d}{d x} (\frac{x ^{2}}{3 + 8 x})

x \cdot y^{^{'}} + y^{2} = 0

What is the integral from 0 to 1 of (65)/(x^5) ?
The integral from 0 to 1 of (65)/(x^5) is diverges