What is the derivative of (x^3)/(10(x-2)) ?

The derivative of (x^3)/(10(x-2)) is (x^2(x-3))/(5(x-2)^2)

What is the first derivative of (x^3)/(10(x-2)) ?

The first derivative of (x^3)/(10(x-2)) is (x^2(x-3))/(5(x-2)^2)

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derivative of

\frac{x ^{3}}{10 ( x - 2 )}

\frac{x ^{2} ( x - 3 )}{5 ( x - 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{10 ( x - 2 )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{10} \frac{d}{d x} (\frac{x ^{3}}{x - 2})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{10} \cdot \frac{\frac{d}{d x} ( x ^{3} ) ( x - 2 ) - \frac{d}{d x} ( x - 2 ) x ^{3}}{( x - 2 ) ^{2}}

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (x - 2) = 1

= \frac{1}{10} \cdot \frac{3 x ^{2} ( x - 2 ) - 1 \cdot x ^{3}}{( x - 2 ) ^{2}}

Simplify

\frac{1}{10} \cdot \frac{3 x ^{2} ( x - 2 ) - 1 \cdot x ^{3}}{( x - 2 ) ^{2}} : \frac{x ^{2} ( x - 3 )}{5 ( x - 2 ) ^{2}}

= \frac{x ^{2} ( x - 3 )}{5 ( x - 2 ) ^{2}}

f (t) = 1 - t

\int 10 cos^{5} (x) sin^{4} (x) d x

f (x) = 3 + 8 ln (x), at x = 1

(2 x^{3}) (4 x^{2})

\int_{0}^{7} 4 x + 5 - x d x

What is the derivative of (x^3)/(10(x-2)) ?
The derivative of (x^3)/(10(x-2)) is (x^2(x-3))/(5(x-2)^2)
What is the first derivative of (x^3)/(10(x-2)) ?
The first derivative of (x^3)/(10(x-2)) is (x^2(x-3))/(5(x-2)^2)