What is the integral of (1/(sqrt(x-1))) ?

The integral of (1/(sqrt(x-1))) is 2sqrt(x-1)+C

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integral of (1/(sqrt(x-1)))

\int (\frac{1}{x - 1}) d x

2 x - 1 + C

Solution steps

\int \frac{1}{x - 1} d x

Apply u-substitution

: \int 2 d u

= \int 2 d u

Integral of a constant:

\int a d x = a x

= 2 u

Substitute back

u = x - 1

= 2 x - 1

Add a constant to the solution

= 2 x - 1 + C

\frac{\partial}{\partial x} (e^{y} \cdot sin (x))

y^{^{''}} + 12 x = 0, y (0) = - 4, y^{^{'}} (0) = 5

\frac{\partial}{\partial x} (\frac{6 y}{x + y})

\int e^{x} \cdot (1 - e^{x})^{- 1} d x

\frac{d}{d x} (2 x^{3} e^{x})

What is the integral of (1/(sqrt(x-1))) ?
The integral of (1/(sqrt(x-1))) is 2sqrt(x-1)+C