What is laplacetransform-3sin(2t) ?

The answer to laplacetransform-3sin(2t) is -6/(s^2+4)

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laplacetransform-3sin(2t)

laplace transform

- 3 sin (2 t)

- \frac{6}{s ^{2} + 4}

Solution steps

L {- 3 sin (2 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 3 L {sin (2 t)}

L {sin (2 t)} : \frac{2}{s ^{2} + 4}

= - 3 \cdot \frac{2}{s ^{2} + 4}

Refine

- 3 \frac{2}{s ^{2} + 4} : - \frac{6}{s ^{2} + 4}

= - \frac{6}{s ^{2} + 4}

\int x^{\frac{3}{2}} + 2 x + 1 d x

x y^{^{'}} + y = 32 x

\int ∣ x - 4 ∣ d x

\frac{d}{d x} (x^{3} - 5 x + 3)

x \to 1 - lim (x^{\frac{1}{1 - x}})

What is laplacetransform-3sin(2t) ?
The answer to laplacetransform-3sin(2t) is -6/(s^2+4)