What is the integral of 0.06e^{0.01x} ?

The integral of 0.06e^{0.01x} is 6e^{0.01x}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 0.06e^{0.01x}

\int 0.06 e^{0.01 x} d x

6 e^{0.01 x} + C

Solution steps

\int 0.06 e^{0.01 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 0.06 \cdot \int e^{0.01 x} d x

Apply u-substitution

: \int e^{u} \frac{1}{0.01} d u

= 0.06 \cdot \int e^{u} \frac{1}{0.01} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 0.06 \cdot \frac{1}{0.01} \cdot \int e^{u} d u

Simplify

= 0.06 \cdot 100 \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= 0.06 \cdot 100 e^{u}

Substitute back

u = 0.01 x

= 0.06 \cdot 100 e^{0.01 x}

Simplify

= 6 e^{0.01 x}

Add a constant to the solution

= 6 e^{0.01 x} + C

\int \frac{2 x + 1}{x} d x

\frac{\partial}{\partial y} (2 x y - 6 y)

\int e^{- \frac{1}{x}} d x

\frac{\partial}{\partial x} (f (x, y) (x + y))

\int_{0}^{1} \frac{r ^{3}}{4 + r ^{2}} d r

What is the integral of 0.06e^{0.01x} ?
The integral of 0.06e^{0.01x} is 6e^{0.01x}+C