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Popular >

y^{''}+2y^'+2=0

Solution

y^{^{''}} + 2 y^{^{'}} + 2 = 0

Solution

y = c_{1} + c_{2} e^{- 2 t} - t

Solution steps

y^{''} (t) + 2 y^{'} (t) + 2 = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- 2 t} - t

y = c_{1} + c_{2} e^{- 2 t} - t

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Frequently Asked Questions (FAQ)

What is the solution for y^{''}+2y^'+2=0 ?
The solution for y^{''}+2y^'+2=0 is y=c_{1}+c_{2}e^{-2t}-t