What is the integral of x/3*sin(x^2) ?

The integral of x/3*sin(x^2) is -1/6 cos(x^2)+C

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integral of x/3*sin(x^2)

\int \frac{x}{3} \cdot sin (x^{2}) d x

- \frac{1}{6} cos (x^{2}) + C

Solution steps

\int \frac{x}{3} sin (x^{2}) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int x sin (x^{2}) d x

Apply u-substitution

: \int \frac{sin ( u )}{2} d u

= \frac{1}{3} \cdot \int \frac{sin ( u )}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \frac{1}{2} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{1}{3} \cdot \frac{1}{2} (- cos (u))

Substitute back

u = x^{2}

= \frac{1}{3} \cdot \frac{1}{2} (- cos (x^{2}))

Simplify

\frac{1}{3} \cdot \frac{1}{2} (- cos (x^{2})) : - \frac{1}{6} cos (x^{2})

= - \frac{1}{6} cos (x^{2})

Add a constant to the solution

= - \frac{1}{6} cos (x^{2}) + C

\int (x) d x

12 x^{2} - 8 x - 4

\int \frac{1}{e ^{x} - 1} d x

y^{^{''}} - 4 y^{^{'}} - 12 y = sin (2 x)

f (x) = \frac{2}{x - 2}, at x = - 4

What is the integral of x/3*sin(x^2) ?
The integral of x/3*sin(x^2) is -1/6 cos(x^2)+C