What is the derivative of h(x)= 1/(x^5) ?

The derivative of h(x)= 1/(x^5) is -5/(x^6)

What is the first derivative of h(x)= 1/(x^5) ?

The first derivative of h(x)= 1/(x^5) is -5/(x^6)

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derivative of

h (x) = \frac{1}{x ^{5}}

- \frac{5}{x ^{6}}

Solution steps

\frac{d}{d x} (\frac{1}{x ^{5}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} (x^{- 5})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 5 x^{- 5 - 1}

Simplify

- 5 x^{- 5 - 1} : - \frac{5}{x ^{6}}

= - \frac{5}{x ^{6}}

\frac{\partial}{\partial x} (π x x^{2} + h^{2})

\int \frac{( e ^{x} - e ^{- x} )}{2} d x

x^{2} - 25 ln (x^{2})

2 e^{- t}

f (x) = - 9 x^{- \frac{1}{9}}

What is the derivative of h(x)= 1/(x^5) ?
The derivative of h(x)= 1/(x^5) is -5/(x^6)
What is the first derivative of h(x)= 1/(x^5) ?
The first derivative of h(x)= 1/(x^5) is -5/(x^6)