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Popular >

d/(da)(sin(a)+sin(2a)+sin(3a))

Solution

\frac{d}{d a} (sin (a) + sin (2 a) + sin (3 a))

Solution

cos (a) + cos (2 a) \cdot 2 + cos (3 a) \cdot 3

Solution steps

\frac{d}{d a} (sin (a) + sin (2 a) + sin (3 a))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d a} (sin (a)) + \frac{d}{d a} (sin (2 a)) + \frac{d}{d a} (sin (3 a))

\frac{d}{d a} (sin (a)) = cos (a)

\frac{d}{d a} (sin (2 a)) = cos (2 a) \cdot 2

\frac{d}{d a} (sin (3 a)) = cos (3 a) \cdot 3

= cos (a) + cos (2 a) \cdot 2 + cos (3 a) \cdot 3

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Frequently Asked Questions (FAQ)

What is the d/(da)(sin(a)+sin(2a)+sin(3a)) ?
The d/(da)(sin(a)+sin(2a)+sin(3a)) is cos(a)+cos(2a)*2+cos(3a)*3
What is the first d/(da)(sin(a)+sin(2a)+sin(3a)) ?
The first d/(da)(sin(a)+sin(2a)+sin(3a)) is cos(a)+cos(2a)*2+cos(3a)*3