What is the integral of 6x^2+16x-10 ?

The integral of 6x^2+16x-10 is 2x^3+8x^2-10x+C

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integral of 6x^2+16x-10

\int 6 x^{2} + 16 x - 10 d x

2 x^{3} + 8 x^{2} - 10 x + C

Solution steps

\int 6 x^{2} + 16 x - 10 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 6 x^{2} d x + \int 16 x d x - \int 10 d x

\int 6 x^{2} d x = 2 x^{3}

\int 16 x d x = 8 x^{2}

\int 10 d x = 10 x

= 2 x^{3} + 8 x^{2} - 10 x

Add a constant to the solution

= 2 x^{3} + 8 x^{2} - 10 x + C

\frac{\partial}{\partial y} (sin (π (5 x - 2 y)))

\int cosh^{2} (x) d x

\int y e^{- 3 y} d y

\frac{d}{d x} ((x^{2} + 3 x)^{4})

X^{\frac{1}{5}}

What is the integral of 6x^2+16x-10 ?
The integral of 6x^2+16x-10 is 2x^3+8x^2-10x+C