What is the derivative of 1-4/(x^2) ?

The derivative of 1-4/(x^2) is 8/(x^3)

What is the first derivative of 1-4/(x^2) ?

The first derivative of 1-4/(x^2) is 8/(x^3)

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\frac{d}{d x} (1 - \frac{4}{x ^{2}})

\frac{8}{x ^{3}}

Solution steps

\frac{d}{d x} (1 - \frac{4}{x ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (\frac{4}{x ^{2}})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (\frac{4}{x ^{2}}) = - \frac{8}{x ^{3}}

= 0 - (- \frac{8}{x ^{3}})

Simplify

= \frac{8}{x ^{3}}

n = 1 \sum \infty 2^{n} x^{n - 1}

(\frac{4}{3} π r^{3})^{^{'}}

\int - (x - 1)^{2} d x

f (x) = x^{2} e^{6 x}

\frac{d}{d x} (cos (x) - 4 tan (x))

What is the derivative of 1-4/(x^2) ?
The derivative of 1-4/(x^2) is 8/(x^3)
What is the first derivative of 1-4/(x^2) ?
The first derivative of 1-4/(x^2) is 8/(x^3)