What is the derivative of 6cos(t)-2sin(t) ?

The derivative of 6cos(t)-2sin(t) is -6sin(t)-2cos(t)

What is the first derivative of 6cos(t)-2sin(t) ?

The first derivative of 6cos(t)-2sin(t) is -6sin(t)-2cos(t)

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derivative of

6 cos (t) - 2 sin (t)

- 6 sin (t) - 2 cos (t)

Solution steps

\frac{d}{d t} (6 cos (t) - 2 sin (t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (6 cos (t)) - \frac{d}{d t} (2 sin (t))

\frac{d}{d t} (6 cos (t)) = - 6 sin (t)

\frac{d}{d t} (2 sin (t)) = 2 cos (t)

= - 6 sin (t) - 2 cos (t)

f (t) = t^{3} - 27 t + 5

\int_{0}^{1} \frac{5}{4 - x ^{2}} d x

y = ln (x^{4} - 4095), (8, 0)

\int - sec (x) tan (x) d x

\frac{d}{d x} (ln (x + x^{2} - 9))

What is the derivative of 6cos(t)-2sin(t) ?
The derivative of 6cos(t)-2sin(t) is -6sin(t)-2cos(t)
What is the first derivative of 6cos(t)-2sin(t) ?
The first derivative of 6cos(t)-2sin(t) is -6sin(t)-2cos(t)