What is the tangent of 3x^2-4x+6,\at x=2 ?

The tangent of 3x^2-4x+6,\at x=2 is y=8x-6

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tangent of 3x^2-4x+6,\at x=2

tangent of

3 x^{2} - 4 x + 6, at x = 2

y = 8 x - 6

Solution steps

Find the tangent point:

(2, 10)

Find the slope of

y = 3 x^{2} - 4 x + 6 : \frac{d y}{d x} = 6 x - 4

Compute the slope of

y = 3 x^{2} - 4 x + 6

x = 2 : m = 8

Find the line with slope m=

8

and passing through

(2, 10) : y = 8 x - 6

y = 8 x - 6

y^{^{''}} + 4 y = 0, y (0) = 1, y (1) = 0

\frac{d}{d t} (a e^{t} cos (2 t) + b e^{t} sin (2 t))

x \to 0 lim ((1 + x)^{2} - 1)

x \to 1 lim (6 x^{2} + 1)

What is the tangent of 3x^2-4x+6,\at x=2 ?
The tangent of 3x^2-4x+6,\at x=2 is y=8x-6