What is the derivative of y=10csc(5x^5-4x+4) ?

The derivative of y=10csc(5x^5-4x+4) is -10cot(5x^5-4x+4)csc(5x^5-4x+4)(25x^4-4)

What is the first derivative of y=10csc(5x^5-4x+4) ?

The first derivative of y=10csc(5x^5-4x+4) is -10cot(5x^5-4x+4)csc(5x^5-4x+4)(25x^4-4)

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derivative of

y = 10 csc (5 x^{5} - 4 x + 4)

- 10 cot (5 x^{5} - 4 x + 4) csc (5 x^{5} - 4 x + 4) (25 x^{4} - 4)

Solution steps

\frac{d}{d x} (10 csc (5 x^{5} - 4 x + 4))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 10 \frac{d}{d x} (csc (5 x^{5} - 4 x + 4))

Apply the chain rule:

- cot (5 x^{5} - 4 x + 4) csc (5 x^{5} - 4 x + 4) \frac{d}{d x} (5 x^{5} - 4 x + 4)

= - cot (5 x^{5} - 4 x + 4) csc (5 x^{5} - 4 x + 4) \frac{d}{d x} (5 x^{5} - 4 x + 4)

\frac{d}{d x} (5 x^{5} - 4 x + 4) = 25 x^{4} - 4

= 10 (- cot (5 x^{5} - 4 x + 4) csc (5 x^{5} - 4 x + 4) (25 x^{4} - 4))

Simplify

= - 10 cot (5 x^{5} - 4 x + 4) csc (5 x^{5} - 4 x + 4) (25 x^{4} - 4)

\int \frac{3 x ^{2}}{( 1 - x ) ( x ^{2} + x + 1 )} d x

x \to 4 lim (- x^{2} + 6 x - 3)

n = 0 \sum \infty x^{2 n + 1}

\frac{d}{d x} (\frac{1}{1 - 2 x})

y = x sin (x) + 2

What is the derivative of y=10csc(5x^5-4x+4) ?
The derivative of y=10csc(5x^5-4x+4) is -10cot(5x^5-4x+4)csc(5x^5-4x+4)(25x^4-4)
What is the first derivative of y=10csc(5x^5-4x+4) ?
The first derivative of y=10csc(5x^5-4x+4) is -10cot(5x^5-4x+4)csc(5x^5-4x+4)(25x^4-4)