What is the solution for x(dy)/(dx)=2x^2+y,y(1)=3 ?

The solution for x(dy)/(dx)=2x^2+y,y(1)=3 is y=2x^2+x

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x(dy)/(dx)=2x^2+y,y(1)=3

x \frac{d y}{d x} = 2 x^{2} + y, y (1) = 3

y = 2 x^{2} + x

Solution steps

x \frac{d y}{d x} = 2 x^{2} + y

Solve linear ODE:

y = 2 x^{2} + x

y = 2 x^{2} + x

n = 2 \sum \infty \frac{1}{n ^{2} + 5 n + 6}

n = 1 \sum \infty \frac{5 n}{3 n - 1}

\frac{d}{d x} (- \frac{2 x}{x - 1})

f (x) = 7 (2 - 3 x)^{4}

\int \frac{( x ^{am} - x ^{n} )}{x} d x

What is the solution for x(dy)/(dx)=2x^2+y,y(1)=3 ?
The solution for x(dy)/(dx)=2x^2+y,y(1)=3 is y=2x^2+x