What is the integral of cos^3(x/(14)) ?

The integral of cos^3(x/(14)) is 14(sin(x/(14))-(sin^3(x/(14)))/3)+C

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integral of cos^3(x/(14))

\int cos^{3} (\frac{x}{14}) d x

14 (sin (\frac{x}{14}) - \frac{sin ^{3} ( \frac{x}{14} )}{3}) + C

Solution steps

\int cos^{3} (\frac{x}{14}) d x

Apply u-substitution

: \int cos^{3} (u) \cdot 14 d u

= \int cos^{3} (u) \cdot 14 d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 14 \cdot \int cos^{3} (u) d u

Rewrite using trig identities

= 14 \cdot \int (1 - sin^{2} (u)) cos (u) d u

Apply u-substitution

: \int 1 - v^{2} d v

= 14 \cdot \int 1 - v^{2} d v

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 14 (\int 1 d v - \int v^{2} d v)

\int 1 d v = v

\int v^{2} d v = \frac{v ^{3}}{3}

= 14 (v - \frac{v ^{3}}{3})

Substitute back

= 14 (sin (\frac{x}{14}) - \frac{sin ^{3} ( \frac{x}{14} )}{3})

Add a constant to the solution

= 14 (sin (\frac{x}{14}) - \frac{sin ^{3} ( \frac{x}{14} )}{3}) + C

\frac{\partial}{\partial x} (e^{5 x yz - 6})

\int 1 + 3 x^{2} y^{2} d y

\frac{d}{d x} (- 12)

\frac{d ^{2}}{d x ^{2}} ((4 x + 3) (2 x^{2} + 7 x - 1))

e^{\frac{- x ^{2}}{2}}

What is the integral of cos^3(x/(14)) ?
The integral of cos^3(x/(14)) is 14(sin(x/(14))-(sin^3(x/(14)))/3)+C