What is the derivative of x^4+6x ?

The derivative of x^4+6x is 4x^3+6

What is the first derivative of x^4+6x ?

The first derivative of x^4+6x is 4x^3+6

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derivative of

x^{4} + 6 x

4 x^{3} + 6

Solution steps

\frac{d}{d x} (x^{4} + 6 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (6 x)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (6 x) = 6

= 4 x^{3} + 6

f (x) = e^{x} sin (x)

\frac{d}{d x} (x^{2} x^{2} + 1)

x \to 0 - lim (\frac{5 x}{x})

\int y sin (y) d y

\int \frac{1}{( x ^{2} - 4 x ) ^{\frac{3}{2}}} d x

What is the derivative of x^4+6x ?
The derivative of x^4+6x is 4x^3+6
What is the first derivative of x^4+6x ?
The first derivative of x^4+6x is 4x^3+6