What is (\partial)/(\partial x)(tan(xy)+ye^{3x}) ?

The answer to (\partial)/(\partial x)(tan(xy)+ye^{3x}) is sec^2(xy)y+ye^{3x}*3

Popular >

(\partial)/(\partial x)(tan(xy)+ye^{3x})

\frac{\partial}{\partial x} (tan (x y) + y e^{3 x})

sec^{2} (x y) y + y e^{3 x} \cdot 3

Solution steps

\frac{\partial}{\partial x} (tan (x y) + y e^{3 x})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (tan (x y)) + \frac{\partial}{\partial x} (y e^{3 x})

\frac{\partial}{\partial x} (tan (x y)) = sec^{2} (x y) y

\frac{\partial}{\partial x} (y e^{3 x}) = y e^{3 x} \cdot 3

= sec^{2} (x y) y + y e^{3 x} \cdot 3

y^{^{'}} + y = e^{- t} sin (t)

cos (t)

\frac{\partial}{\partial x} ((4 x^{4} y^{2} + 9)^{2})

n = 1 \sum \infty (\frac{7}{10})^{n}

\int \frac{1 + e ^{x}}{1 - e ^{x}} d x

What is (\partial)/(\partial x)(tan(xy)+ye^{3x}) ?
The answer to (\partial)/(\partial x)(tan(xy)+ye^{3x}) is sec^2(xy)y+ye^{3x}*3