What is (\partial)/(\partial x)((3x+1)y) ?

The answer to (\partial)/(\partial x)((3x+1)y) is 3y

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(\partial)/(\partial x)((3x+1)y)

\frac{\partial}{\partial x} ((3 x + 1) y)

3 y

Solution steps

\frac{\partial}{\partial x} ((3 x + 1) y)

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y \frac{\partial}{\partial x} (3 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= y (\frac{\partial}{\partial x} (3 x) + \frac{\partial}{\partial x} (1))

\frac{\partial}{\partial x} (3 x) = 3

\frac{\partial}{\partial x} (1) = 0

= y (3 + 0)

Simplify

= 3 y

\int \frac{( x ^{2} + 1 )}{( x - 4 ) ( x - 3 ) ^{2}} d x

y^{^{''}} - 10 y^{^{'}} + 34 y = 0, y (0) = - 2, y^{^{'}} (0) = - 3

\frac{3}{x}, \frac{3}{x ^{2}}, 6

y = 5, y = x^{2} + 1

(x - 2)^{2} - 3 x

What is (\partial)/(\partial x)((3x+1)y) ?
The answer to (\partial)/(\partial x)((3x+1)y) is 3y