What is area y=\sqrt[3]{x},y= 1/x ,x=8 ?

The answer to area y=\sqrt[3]{x},y= 1/x ,x=8 is 45/4-3ln(2)

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area y=\sqrt[3]{x},y= 1/x ,x=8

area

\frac{45}{4} - 3 ln (2)

Decimal Notation

9.17055 \dots

Solution steps

Apply the area formula:

Solve

The area is:

= \frac{45}{4} - 3 ln (2)

\frac{d}{d x} (2 (x - 3))

\frac{d y}{d x} = \frac{( x ^{2} y - 32 )}{16 - x ^{2}} + 2

f (x) = \frac{x ^{2}}{x + 5}, at x = 3

a q^{2}

2 x - x^{2}, 2 x - 4

What is area y=\sqrt[3]{x},y= 1/x ,x=8 ?
The answer to area y=\sqrt[3]{x},y= 1/x ,x=8 is 45/4-3ln(2)