What is the derivative of x^2*ln(7x) ?

The derivative of x^2*ln(7x) is 2xln(7x)+x

What is the first derivative of x^2*ln(7x) ?

The first derivative of x^2*ln(7x) is 2xln(7x)+x

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derivative of

x^{2} \cdot ln (7 x)

2 x ln (7 x) + x

Solution steps

\frac{d}{d x} (x^{2} ln (7 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = ln (7 x)

= \frac{d}{d x} (x^{2}) ln (7 x) + \frac{d}{d x} (ln (7 x)) x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (ln (7 x)) = \frac{1}{x}

= 2 x ln (7 x) + \frac{1}{x} x^{2}

\frac{1}{x} x^{2} = x

= 2 x ln (7 x) + x

\int_{\frac{1}{5}}^{7} 10 x ln (5 x) d x

f (t) = sin (5 t)

\int 125 x^{2} cos (5 x) d x

\frac{\partial}{\partial u} (u^{2} v^{3})

x \to 0 lim (x^{2} - 8)

What is the derivative of x^2*ln(7x) ?
The derivative of x^2*ln(7x) is 2xln(7x)+x
What is the first derivative of x^2*ln(7x) ?
The first derivative of x^2*ln(7x) is 2xln(7x)+x