What is the integral of sin^4(2x)*cos(2x) ?

The integral of sin^4(2x)*cos(2x) is 1/10 sin^5(2x)+C

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integral of sin^4(2x)*cos(2x)

\int sin^{4} (2 x) \cdot cos (2 x) d x

\frac{1}{10} sin^{5} (2 x) + C

Solution steps

\int sin^{4} (2 x) cos (2 x) d x

Apply u-substitution

: \int sin^{4} (u) cos (u) \frac{1}{2} d u

= \int sin^{4} (u) cos (u) \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int sin^{4} (u) cos (u) d u

Apply u-substitution

: \int v^{4} d v

= \frac{1}{2} \cdot \int v^{4} d v

Apply the Power Rule

: \frac{v ^{5}}{5}

= \frac{1}{2} \cdot \frac{v ^{5}}{5}

Substitute back

= \frac{1}{2} \cdot \frac{sin ^{5} ( 2 x )}{5}

Simplify

\frac{1}{2} \cdot \frac{sin ^{5} ( 2 x )}{5} : \frac{1}{10} sin^{5} (2 x)

= \frac{1}{10} sin^{5} (2 x)

Add a constant to the solution

= \frac{1}{10} sin^{5} (2 x) + C

y = \frac{1}{( 1 + c _{1} e ^{- x} )}

\frac{\partial}{\partial x} (e^{x t})

\frac{d}{d x} (\frac{1}{x ^{\frac{1}{3}}})

\int z^{2} sin (x) d x

y^{^{''''}} + y = 0

What is the integral of sin^4(2x)*cos(2x) ?
The integral of sin^4(2x)*cos(2x) is 1/10 sin^5(2x)+C