What is the derivative of 2x^2-9x+10 ?

The derivative of 2x^2-9x+10 is 4x-9

What is the first derivative of 2x^2-9x+10 ?

The first derivative of 2x^2-9x+10 is 4x-9

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\frac{d}{d x} (2 x^{2} - 9 x + 10)

4 x - 9

Solution steps

\frac{d}{d x} (2 x^{2} - 9 x + 10)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (9 x) + \frac{d}{d x} (10)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (9 x) = 9

\frac{d}{d x} (10) = 0

= 4 x - 9 + 0

Simplify

= 4 x - 9

\frac{2 s - 44}{7 s ^{2} - 14 s + 70}

\frac{d y}{d x} - sin (x + y) = 0

\frac{d x}{d y} = \frac{( y - x )}{y + x}

y = 2, y = x^{2} + 1

\frac{d}{d x} ((lo g_{2} (x))^{4})

What is the derivative of 2x^2-9x+10 ?
The derivative of 2x^2-9x+10 is 4x-9
What is the first derivative of 2x^2-9x+10 ?
The first derivative of 2x^2-9x+10 is 4x-9