What is the derivative of x^2-2x+8 ?

The derivative of x^2-2x+8 is 2x-2

What is the first derivative of x^2-2x+8 ?

The first derivative of x^2-2x+8 is 2x-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

x^{2} - 2 x + 8

2 x - 2

Solution steps

\frac{d}{d x} (x^{2} - 2 x + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (2 x) + \frac{d}{d x} (8)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (8) = 0

= 2 x - 2 + 0

Simplify

= 2 x - 2

\int x^{5} 1 + x^{3} d x

x^{2} + 4 x - 11 = - 2 y^{2} - 3 y, (2, - 1)

\int (3 - x)^{- \frac{1}{2}} d x

\frac{d}{d x} (x^{2} + x + 4)

\frac{d h}{d t} = 4 - 16 t^{2}, h (1) = 0

What is the derivative of x^2-2x+8 ?
The derivative of x^2-2x+8 is 2x-2
What is the first derivative of x^2-2x+8 ?
The first derivative of x^2-2x+8 is 2x-2