What is the limit as x approaches 2 of pi^2-2x+5 ?

The limit as x approaches 2 of pi^2-2x+5 is pi^2+1

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limit as x approaches 2 of pi^2-2x+5

x \to 2 lim (π^{2} - 2 x + 5)

π^{2} + 1

Decimal Notation

10.86960 \dots

Solution steps

x \to 2 lim (π^{2} - 2 x + 5)

Plug in the value

x = 2

= π^{2} - 2 \cdot 2 + 5

Simplify

= π^{2} + 1

x (2 x + 7)^{\frac{2}{3}}

t \to 2 lim (8 + t^{3})

y = e^{- x} sin (x), y = - e^{- x} sin (x), 0 \leq x \leq π

\int \frac{cos ( 7 x )}{1 + sin ^{2} ( 7 x )} d x

f (x) = x^{2} (x - 2)^{4}

What is the limit as x approaches 2 of pi^2-2x+5 ?
The limit as x approaches 2 of pi^2-2x+5 is pi^2+1