What is the solution for (y-yx^2)(dy)/(dx)=(y+1)^2 ?

The solution for (y-yx^2)(dy)/(dx)=(y+1)^2 is y=-1-1/(\W(-(sqrt(x-1))/(c_{1)\sqrt{x+1)})}

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(y-yx^2)(dy)/(dx)=(y+1)^2

(y - y x^{2}) \frac{d y}{d x} = (y + 1)^{2}

y = - 1 - \frac{1}{W ( - \frac{x - 1}{c _{1} x + 1} )}

Solution steps

(y - y x^{2}) \frac{d y}{d x} = (y + 1)^{2}

Solve separable ODE:

y = - 1 - \frac{1}{W ( - \frac{x - 1}{c _{1} x + 1} )}

y = - 1 - \frac{1}{W ( - \frac{x - 1}{c _{1} x + 1} )}

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What is the solution for (y-yx^2)(dy)/(dx)=(y+1)^2 ?
The solution for (y-yx^2)(dy)/(dx)=(y+1)^2 is y=-1-1/(\W(-(sqrt(x-1))/(c_{1)\sqrt{x+1)})}