What is the tangent of f(x)=2tan(x),\at x= pi/6 ?

The tangent of f(x)=2tan(x),\at x= pi/6 is y= 8/3 x+2/(sqrt(3))-(4pi)/9

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tangent of f(x)=2tan(x),\at x= pi/6

tangent of

f (x) = 2 tan (x), at x = \frac{π}{6}

y = \frac{8}{3} x + \frac{2}{3} - \frac{4 π}{9}

Solution steps

Find the tangent point:

(\frac{π}{6}, \frac{2}{3})

Find the slope of

f (x) = 2 tan (x) : \frac{df ( x )}{d x} = 2 sec^{2} (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{8}{3}

Find the line with slope m=

\frac{8}{3}

and passing through

(\frac{π}{6}, \frac{2}{3}) : y = \frac{8}{3} x + \frac{2}{3} - \frac{4 π}{9}

y = \frac{8}{3} x + \frac{2}{3} - \frac{4 π}{9}

\frac{d}{d x} (e^{\frac{1}{2 x}})

\int tan (b) x d x

f (x) = tan (e^{x})

10 y^{^{''}} - 10 y^{^{'}} + 65 y = 0

x \to - 3 + lim (\frac{2}{x ^{2} - 9})

What is the tangent of f(x)=2tan(x),\at x= pi/6 ?
The tangent of f(x)=2tan(x),\at x= pi/6 is y= 8/3 x+2/(sqrt(3))-(4pi)/9