What is the tangent of y=-2x^3,(-1,2) ?

The tangent of y=-2x^3,(-1,2) is y=-6x-4

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tangent of y=-2x^3,(-1,2)

tangent of

y = - 2 x^{3}, (- 1, 2)

y = - 6 x - 4

Solution steps

Find the slope of

y = - 2 x^{3} : \frac{d y}{d x} = - 6 x^{2}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 6

Find the line with slope m=

- 6

and passing through

(- 1, 2) : y = - 6 x - 4

y = - 6 x - 4

\int_{0}^{1} \int_{0}^{1} 4 x y e^{- 2 x - y} d y d x

n = 0 \sum \infty (- 1)^{- n}

\int \frac{8}{17} x^{\frac{17}{9}} + C d x

x \to 3 - lim (\frac{x + 2}{x + 3})

\int \frac{x x + x}{x} d x

What is the tangent of y=-2x^3,(-1,2) ?
The tangent of y=-2x^3,(-1,2) is y=-6x-4