What is the limit as x approaches 1-of (x+1)/(x^2-1) ?

The limit as x approaches 1-of (x+1)/(x^2-1) is -infinity

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limit as x approaches 1-of (x+1)/(x^2-1)

x \to 1 - lim (\frac{x + 1}{x ^{2} - 1})

- \infty

Solution steps

x \to 1 - lim (\frac{x + 1}{x ^{2} - 1})

Simplify

\frac{x + 1}{x ^{2} - 1} : \frac{1}{x - 1}

= x \to 1 - lim (\frac{1}{x - 1})

For

x

approaching

1

from the left

, x < 1 \Rightarrow x - 1 < 0

The denominator is a negative quantity approaching 0 from the left

= - \infty

f (x) = (x^{2} - 10)^{4}

\int_{0}^{π} (1 - cos^{2} (x)) d x

h \to 0 lim (h^{4})

(x, y) \to (3, - 3) lim ((e^{- x y}) cos (x + y))

3 x + 8, x^{2} + 2 x + 2, 0, 2

What is the limit as x approaches 1-of (x+1)/(x^2-1) ?
The limit as x approaches 1-of (x+1)/(x^2-1) is -infinity