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Popular >

y^'=2xy,y(1)=1

Solution

y^{^{'}} = 2 x y, y (1) = 1

Solution

y = e^{x^{2} - 1}

Solution steps

y^{'} (x) = 2 x y

Solve separable ODE:

y = e^{x^{2} - 1}

y = e^{x^{2} - 1}

Graph

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x \to - 5 lim (sin (x \cdot π))

(\partial)/(\partial x)((14+17x)y^{tan(x)})

\frac{\partial}{\partial x} ((14 + 17 x) y^{t a n (x)})

integral of 1/((sqrt(x^2+y^2)))

\int \frac{1}{( x ^{2} + y ^{2} )} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=2xy,y(1)=1 ?
The solution for y^'=2xy,y(1)=1 is y=e^{x^2-1}