What is the derivative of g(x)=ln(3x) ?

The derivative of g(x)=ln(3x) is 1/x

What is the first derivative of g(x)=ln(3x) ?

The first derivative of g(x)=ln(3x) is 1/x

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derivative of

g (x) = ln (3 x)

\frac{1}{x}

Solution steps

\frac{d}{d x} (ln (3 x))

Apply the chain rule:

\frac{1}{3 x} \frac{d}{d x} (3 x)

= \frac{1}{3 x} \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= \frac{1}{3 x} \cdot 3

Simplify

\frac{1}{3 x} \cdot 3 : \frac{1}{x}

= \frac{1}{x}

9 x^{\frac{1}{3}} + \frac{9}{2} x^{\frac{4}{3}}

\frac{\partial}{\partial x} (- x e^{(x y)})

\int - 2 x + 18 x^{2} - 4 x^{3} + C d x

\int 2 cos^{3} (x) sin (x) d x

\frac{d}{d x} (2 x x sin (x))

What is the derivative of g(x)=ln(3x) ?
The derivative of g(x)=ln(3x) is 1/x
What is the first derivative of g(x)=ln(3x) ?
The first derivative of g(x)=ln(3x) is 1/x