What is the tangent of 4^{x/(ln(2))},\at x=ln(16) ?

The tangent of 4^{x/(ln(2))},\at x=ln(16) is y=512x+256-2048ln(2)

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tangent of 4^{x/(ln(2))},\at x=ln(16)

tangent of

4^{\frac{x}{l n ( 2 )}}, at x = ln (16)

y = 512 x + 256 - 2048 ln (2)

Solution steps

Find the tangent point:

(ln (16), 256)

Find the slope of

y = 4^{\frac{x}{l n ( 2 )}} : \frac{d y}{d x} = 2 e^{2 x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 512

Find the line with slope m=

512

and passing through

(ln (16), 256) : y = 512 x + 256 - 2048 ln (2)

y = 512 x + 256 - 2048 ln (2)

\int t (t^{2} + 1) d t

(3 x y + y^{2}) d x + (x^{2} + x y) d y = 0

\int_{3}^{5} \frac{1}{5 - x} d x

\frac{3.49}{x ^{0.432}}

\frac{d}{d x} (\frac{1}{3 ( 1 + x ) ^{\frac{2}{3}}})

What is the tangent of 4^{x/(ln(2))},\at x=ln(16) ?
The tangent of 4^{x/(ln(2))},\at x=ln(16) is y=512x+256-2048ln(2)