What is the sum from n=4 to infinity of (3^n)/(14^n) ?

The sum from n=4 to infinity of (3^n)/(14^n) is converges

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sum from n=4 to infinity of (3^n)/(14^n)

n = 4 \sum \infty \frac{3 ^{n}}{1 4 ^{n}}

converges

Solution steps

n = 4 \sum \infty \frac{3 ^{n}}{1 4 ^{n}}

n \to \infty lim (n (\frac{\frac{3 ^{n}}{1 4 ^{n}}}{\frac{3 ^{n + 1}}{1 4 ^{n + 1}}} - 1)) = \infty

L > 1,

by the Raabe's test

= converges

\frac{\partial}{\partial x} (x^{2} e^{x y})

\int - 3 x + 2 d x

25 \cdot 1. 6^{t}

\frac{\partial}{\partial x} (\frac{y}{2 1 + x y})

\int_{1}^{4} 24 t d t

What is the sum from n=4 to infinity of (3^n)/(14^n) ?
The sum from n=4 to infinity of (3^n)/(14^n) is converges