What is the derivative of 2xln(3x+x) ?

The derivative of 2xln(3x+x) is 2ln(3x)+3

What is the first derivative of 2xln(3x+x) ?

The first derivative of 2xln(3x+x) is 2ln(3x)+3

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\frac{d}{d x} (2 x ln (3 x) + x)

2 ln (3 x) + 3

Solution steps

\frac{d}{d x} (2 x ln (3 x) + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x ln (3 x)) + \frac{d x}{d x}

\frac{d}{d x} (2 x ln (3 x)) = 2 (ln (3 x) + 1)

\frac{d x}{d x} = 1

= 2 (ln (3 x) + 1) + 1

Simplify

2 (ln (3 x) + 1) + 1 : 2 ln (3 x) + 3

= 2 ln (3 x) + 3

\frac{\partial}{\partial x} (x + 2 y - 22)

x \to - \infty lim (ln ∣ x ∣)

\frac{\partial}{\partial x} (7 e^{y} - 4 y e^{x})

sin (9 x)

\frac{d}{d x} (e^{m x} m)

What is the derivative of 2xln(3x+x) ?
The derivative of 2xln(3x+x) is 2ln(3x)+3
What is the first derivative of 2xln(3x+x) ?
The first derivative of 2xln(3x+x) is 2ln(3x)+3