What is the tangent of sqrt(x),\at x=4 ?

The tangent of sqrt(x),\at x=4 is y= 1/4 x+1

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tangent of sqrt(x),\at x=4

tangent of

x, at x = 4

y = \frac{1}{4} x + 1

Solution steps

Find the tangent point:

(4, 2)

Find the slope of

y = x : \frac{d y}{d x} = \frac{1}{2 x}

Compute the slope of

y = x

x = 4 : m = \frac{1}{4}

Find the line with slope m=

\frac{1}{4}

and passing through

(4, 2) : y = \frac{1}{4} x + 1

y = \frac{1}{4} x + 1

x \to \infty lim (x^{\frac{5}{x}})

\int_{0}^{π} sin (x) x^{5} d x

x \to - 2 - lim (\frac{- 4 x}{x + 2})

\int x (3 x - 1)^{10} d x

f (x) = \frac{6 x}{x ^{2} + 5}

What is the tangent of sqrt(x),\at x=4 ?
The tangent of sqrt(x),\at x=4 is y= 1/4 x+1