What is the derivative of x/((x^2-1^2)) ?

The derivative of x/((x^2-1^2)) is (-3x^2-1)/((x^2-1)^3)

What is the first derivative of x/((x^2-1^2)) ?

The first derivative of x/((x^2-1^2)) is (-3x^2-1)/((x^2-1)^3)

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\frac{d}{d x} (\frac{x}{( x ^{2} - 1 ) ^{2}})

\frac{- 3 x ^{2} - 1}{( x ^{2} - 1 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{x}{( x ^{2} - 1 ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d x}{d x} ( x ^{2} - 1 ) ^{2} - \frac{d}{d x} ( ( x ^{2} - 1 ) ^{2} ) x}{( ( x ^{2} - 1 ) ^{2} ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} ((x^{2} - 1)^{2}) = 4 x (x^{2} - 1)

= \frac{1 \cdot ( x ^{2} - 1 ) ^{2} - 4 x ( x ^{2} - 1 ) x}{( ( x ^{2} - 1 ) ^{2} ) ^{2}}

Simplify

\frac{1 \cdot ( x ^{2} - 1 ) ^{2} - 4 x ( x ^{2} - 1 ) x}{( ( x ^{2} - 1 ) ^{2} ) ^{2}} : \frac{- 3 x ^{2} - 1}{( x ^{2} - 1 ) ^{3}}

= \frac{- 3 x ^{2} - 1}{( x ^{2} - 1 ) ^{3}}

f (x) = \frac{e ^{x}}{x ^{6}}

\int 4 t^{3} t^{2} + 1 d t

y^{^{'}} = \frac{2 y}{x} - x^{2} y^{2}

x \to \infty lim (x^{s i n (x)})

\frac{\partial}{\partial x} (y x - y^{2} - 2 x + 7 y)

What is the derivative of x/((x^2-1^2)) ?
The derivative of x/((x^2-1^2)) is (-3x^2-1)/((x^2-1)^3)
What is the first derivative of x/((x^2-1^2)) ?
The first derivative of x/((x^2-1^2)) is (-3x^2-1)/((x^2-1)^3)