What is the derivative of f(x)=x^4+4x ?

The derivative of f(x)=x^4+4x is 4x^3+4

What is the first derivative of f(x)=x^4+4x ?

The first derivative of f(x)=x^4+4x is 4x^3+4

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derivative of

f (x) = x^{4} + 4 x

4 x^{3} + 4

Solution steps

\frac{d}{d x} (x^{4} + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (4 x)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (4 x) = 4

= 4 x^{3} + 4

\int (1 + tan (x))^{2} d x

y^{2} + y

x \to 3 - lim (\frac{- x}{x - 3})

ln (A x^{4} + B)

x \to - 3 lim (∣ x - 1 ∣)

What is the derivative of f(x)=x^4+4x ?
The derivative of f(x)=x^4+4x is 4x^3+4
What is the first derivative of f(x)=x^4+4x ?
The first derivative of f(x)=x^4+4x is 4x^3+4