What is the derivative of 2*cos(2x) ?

The derivative of 2*cos(2x) is -4sin(2x)

What is the first derivative of 2*cos(2x) ?

The first derivative of 2*cos(2x) is -4sin(2x)

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\frac{d}{d x} (2 \cdot cos (2 x))

- 4 sin (2 x)

Solution steps

\frac{d}{d x} (2 cos (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (cos (2 x))

Apply the chain rule:

- sin (2 x) \frac{d}{d x} (2 x)

= - sin (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 2 (- sin (2 x) \cdot 2)

Simplify

= - 4 sin (2 x)

\frac{\partial}{\partial x} (cos (π x) - x^{2} y + e^{x z} + yz)

f (x) = - e^{x} x + 2 e^{x}

\frac{d}{d x} (3 x^{2} cos (x) - x^{3} sin (x))

\int \frac{22}{( x ^{2} - 1 ) ^{2}} d x

x \to 0 lim (x (csc (x)))

What is the derivative of 2*cos(2x) ?
The derivative of 2*cos(2x) is -4sin(2x)
What is the first derivative of 2*cos(2x) ?
The first derivative of 2*cos(2x) is -4sin(2x)